Monday

Genetics Lecture 16, 10/6 - Infectious Heredity, Bacteria, Mapping


Chapter 9 overheads available here.http://docs.google.com/Presentation?id=dhqwrndc_393g3pmdwfm

Chapter 6 overheads available here. http://docs.google.com/Presentation?id=dhqwrndc_384d93nzm8c


Infectious heredity
: a trait that is passed to a eukaryotic cell by living in symbiosis with a microorganism

  • • Example of infectious heredity in Paramecium urelia
    • o Killer phenotype → these cells secrete a compound which is toxic to any cell not having the kller phenotype
    • • Two things necessary for killer phenotype
      • o Kappa particle a microorganism in the cytoplasm
      • o Dominant k allele
    • o Paramecium can undergo conjugation (Sexual reproduction) → Genetic exchange occurs during conjugation. Also during conjugation cytoplasmic exchange sometimes occurs.
    • • Cytoplasmic exchange is necessary to pass on the killer phenotype
    • • For a Heterozygote that undergoes autogamy (asexual reproduction) it will produce two offspring → One homozygous dominant and one homozygous recessive.
  • Maternal Effect – (Non mendelian heredity) (7:50)
    • o Gene products in the egg which influence the phenotype. This gene product influences the early development of your offspring.
    • o EX. Shell coiling in the snail (linnea peregra)
      • • Two types of coils: dextral - right handed coil (dominant trait) and sinistral: left handed coil (recessive trait)
      • • Snails are hermaphrodites. They can undergo sexual reproduction or self fertilization.
      • • The offspring’s phenotype is directly based on the genotype of the mother. Not based on the offspring’s genotype. An offspring from a mom with a dominant D will be dextral. A mom with a recessive d will be sinistral.
    • • Maternal genotype to offspring phenotype.
  • Chapter 6 bacteria and bacteriophages (19:35)
  • • Bacterial growth – two types of growth media
    • o Complete media – media which contains all of the necessary components for growth. Also referred to as rich media.
    • o Minimal media – contains basic chemical requirements for growth.
    • o Auxotrophic mutant – any strain which fails to grow on minimal media. Typically has a mutation in a gene necessary for making some component.
  • • Bacterial growth curve:
    • o Lag phase: immediately after entereing the culture, period of little or not growth. Adjustment time
    • o Log phase: cells begin to grow rapidly. Doubling of the population every 30 to 60 minutes
    • o Stationary phase: begins when some component of your media becomes limiting. Populations level off and there is little to no new growth
  • How they exchange information. (32:00)
    • o In 1946 the first report was issued that bacterial cells can undergo conjugation: one bacterial cell sending information to a second.
    • o Experiments which showed conjugation could occur (34:20)
      • • Start with Two strains in complete media, both auxotrophs (see pic). They are auxotrophic for different genes.
      • • Plated each strain on minimal media as a control. Neither strain grow on minimal media. In a different culture the two strains were mixed the two strains together and incubated overnight.
      • • Took the mix and plated on minimal media – produced some prototrophs. This occurred at a rate of 1 in every 10^7 colonies.
      • • This indicates that some exchange of information has occurred.
      • • Bacteria have the ability to undergo unidirectional transfer.
      • • F+ cell is a cell that can donate information. F- cell receives information. Following the transfer the F+ cell becomes F- and vice versa.
    • o Does transfer require physical contact between the cells? DAVIS U-TUBE experiment (40:45)
      • • Take auxotrophic strains and place them in a u tube. Inbetween the strains place a glass filter - Allows media to be exchanged BUT Cells cannot pass across the filter
      • • Plate media from both sides of the filter on to minimal media – found no growth from either side.
      • • Indicates that- physical contact is required for gene transfer. This becomes the basis for mapping bacterial genes.
  • • 1950 – scientist working with an F+ strain treating it with nitrogen mustard. Found a strain which underwent recombination more frequently . . . 1 in every 10^4 cells. Hfr strains – high frequency recombination strains.
    • o Basic mapping experiment to find how Hfr gets to F-. (47:35)
      • • Hfr strain with four mutations
      • • F- strain without theses mutations
      • • 1.) Mix the Hfr strain and the F- strain then (2.)Give them 10 min for conjugation. (3) Pull out some cells, blend your cells. Why? Conjugation is facilitated through a sexpilus long projection from one cell to another through which DNA can pass.
      • • plate these cells to look for the passage of the mutation
      • • repeat at 15 minutes steps 2 and 3
      • • at 20 minutes repeat steps 2 and 3
      • • at 30 minutes repeat steps 2 and 3
      • • based on your data (results of Hfr mapping)
        • azir tons leu+ gal+

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